Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Review Exercises - Page 818: 4

Answer

center is at $(5,-3)$ and the radius is $7$.

Work Step by Step

The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$. Hence here the center is at $(5,-3)$ and the radius is $7$.
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