Answer
$(x-3)^2+(y+2)^2=25$
Work Step by Step
The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$. Hence: $(x-3)^2+(y-(-2))^2=5^2$ is equal to $(x-3)^2+(y+2)^2=25$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 10 - Review Exercises - Page 818: 3
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