## Intermediate Algebra for College Students (7th Edition)

$n=\dfrac{x_1+x_2+x_3}{A}$
Multiply $n$ to both sides to find: $n \cdot A = n \cdot \dfrac{x_1+x_2+x_3}{n} \\nA = x_1+x_2+x_3$ Divide by $A$ on both sides to find: $\dfrac{nA}{A} = \dfrac{x_1+x_2+x_3}{A} \\n=\dfrac{x_1+x_2+x_3}{A}$