Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set: 74

Answer

$n=\dfrac{x_1+x_2+x_3}{A}$

Work Step by Step

Multiply $n$ to both sides to find: $n \cdot A = n \cdot \dfrac{x_1+x_2+x_3}{n} \\nA = x_1+x_2+x_3$ Divide by $A$ on both sides to find: $\dfrac{nA}{A} = \dfrac{x_1+x_2+x_3}{A} \\n=\dfrac{x_1+x_2+x_3}{A}$
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