Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 68: 70


$d=\dfrac{L-a}{n-1} $

Work Step by Step

Subtract $a$ on both sides to find: $L-a=(n-1)d$ Divide by $n-1$ on both sides to find: $\dfrac{L-a}{n-1} = \dfrac{(n-1)d}{n-1} \\\dfrac{L-a}{n-1} = d \\d=\dfrac{L-a}{n-1} $
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