## Intermediate Algebra for College Students (7th Edition)

$a=\dfrac{2s-2vt}{t^2}$
Subtract $vt$ from both sides to find: $s-vt=\frac{1}{2}at^2$ Multiply $2$ to both sides to find: $2(s-vt)= 2 \cdot \frac{1}{2}at^2 \\2s-2vt=at^2$ Divide both sides by $t^2$ to find: $\dfrac{2s-2vt}{t^2}=\dfrac{at^2}{t^2} \\\dfrac{2s-2vt}{t^2}=a \\a=\dfrac{2s-2vt}{t^2}$