Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set: 68

Answer

$a=\dfrac{2s-2vt}{t^2}$

Work Step by Step

Subtract $vt$ from both sides to find: $s-vt=\frac{1}{2}at^2$ Multiply $2$ to both sides to find: $2(s-vt)= 2 \cdot \frac{1}{2}at^2 \\2s-2vt=at^2$ Divide both sides by $t^2$ to find: $\dfrac{2s-2vt}{t^2}=\dfrac{at^2}{t^2} \\\dfrac{2s-2vt}{t^2}=a \\a=\dfrac{2s-2vt}{t^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.