Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set: 62

Answer

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Work Step by Step

Divide both sides by $x_2-x_1$ to find: $\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{m(x_2-x_1)}{x_2-x_1} \\\dfrac{y_2-y_1}{x_2-x_1}=m \\m=\dfrac{y_2-y_1}{x_2-x_1}$
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