#### Answer

conditional equation

#### Work Step by Step

Distribute $\frac{1}{2}$ then combine like terms to obtain:
$\frac{1}{2}(6z) + \frac{1}{2}(20) -8 = 2z - 2(4)
\\3z + 10 -8 = 2z - 8
\\3z + 2 = 2z - 8$
Subtract $2z$ and $2$ on both sides of the equation to obtain:
$3z-2z=-8-2
\\z = -10$
The given equation has one solution so it is a conditional equation.