Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set: 13

Answer

$y=-4$

Work Step by Step

Subtract $8y$ and subtract $9$ on both sides, and then combine like terms to obtain: $-3-9=11y-8y \\ -12=3y$ Divide by 3 on both sides to obtain: $\dfrac{-12}{3}=y \\-4=y$ Check: $\begin{array}{ccc} &8(-4)-3&=&11(-4)+9 \\&-32-3 &= &-44+9 \\&-35&=&-35\end{array}$
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