Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set: 26

Answer

$x=30$

Work Step by Step

For easier work, it is better to get rid of the fractions. This can be achieved by multiplying the LCD $30$ on both sides of the equation to obtain: $30(\frac{x}{5}) = 30(\frac{x}{6}+1) \\\frac{30x}{5} = \frac{30x}{6} +30 \\6x = 5x +30$ Subtract $5x$ on both sidesto obtain: $6x-5x=30 \\x=30$ Check: $\begin{array}{ccc} &\frac{30}{5} &= &\frac{30}{6} +1 \\&6 &= &5+1 \\&6 &= &6 \end{array}$
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