Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 50: 30



Work Step by Step

For easier work, it is better to get rid of the fractions. This can be achieved by multiplying the LCD of $4$ on both sides of the equation to obtain: $4(\frac{x}{2}) = 4(\frac{3x}{4}+5) \\\frac{4x}{2} = \frac{12x}{4} +20 \\2x = 3x+20$ Subtract $2x$ and $20$ on both sides to obtain: $-20=3x-2x \\-20=x$ Check: $\begin{array}{ccc} &\frac{-20}{2} &= &\frac{3(-20)}{4}+5 \\&-10 &= &\frac{-60}{4}+5 \\&-10 &= &-15+5 \\&-10 &= &-10\end{array}$
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