Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises: 67

Answer

$\frac{72}{11}$

Work Step by Step

Multiply 12 (the LCD of the fractions) on both sides of the equation to obtain: $12(\frac{2x}{3}) = 12(6-\frac{x}{4}) \\\frac{24x}{3}= 72- \frac{12x}{4} \\8x=72-3x$ Add $3x$ on both sides of the equation to obtain: $11x=72$ Divide 11 on both sides of the equation to obtain: $x = \frac{72}{11}$
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