## Intermediate Algebra for College Students (7th Edition)

$2$
Multiply by 18 (the LCD of the two fractions) on both sides of the equation to obtain: $18(\frac{2x}{3}) = 18(\frac{x}{6}+1) \\\frac{36x}{3} = \frac{18x}{6} + 18 \\12x = 3x+18$ Subtract $3x$ on both sides of the equation to obtain: $9x=18$ Divide by 9 on both sides of the equation to obtain: $x = \frac{18}{9} \\x=2$