## Intermediate Algebra for College Students (7th Edition)

$-3$
Distribute $2$ and $3$ to obtain: $2x-8+3x+15=2x-2 \\5x+7=2x-2$ Subtract $2x$ on both sides of the equation to obtain: $3x+7=-2$ Subtract $7$ on both sides of the equation to obtain: $3x = -9$ Divide by 3 on both sides of the equation to obtain: $x=\frac{-9}{3} \\x=-3$ Check: $2(-3-4)+3(-3+5)=2(-3)-2 \\2(-7) + 3(2)=-6-2 \\-14+6=-8 \\-8=-8$