## Intermediate Algebra for College Students (7th Edition)

$2$
Multiply by 10 (the LCD of the fractions) on both sides of the equation to obtain: $10(\frac{x}{2}-\frac{1}{10}) = 10(\frac{x}{5}+\frac{1}{2}) \\\frac{10x}{2} -\frac{10}{10}= \frac{10x}{5} + \frac{10}{2} \\5x -1= 2x+5$ Subtract by $2x$ on both sides of the equation to obtain: $3x-1=5$ Add $1$ to both sides of the equation to obtain: $3x=6$ Divide by 3 on both sides of the equation to obtain: $x = \frac{6}{3} \\x=2$