Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Mid-Chapter Check Point - Page 53: 6



Work Step by Step

$7x - [8 - 3(2x - 5)]$ Work in parentheses. Expand $3(2x - 5)$ = $6x-15$ Rewrite the equation: $=7x -(8-(6x-15))$ $=7x-(8-6x+15)$ $=7x-(-6x+23)$ $=7x+6x-23$ $=13x-23$
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