Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Mid-Chapter Check Point - Page 53: 12

Answer

$-4$

Work Step by Step

Evaluate applying the order of operations. $(6-9)(8-12)\displaystyle \div\frac{5^{2}+4\div 2}{8^{2}-9^{2}+8}=\qquad$... Parentheses first, $=(-3)(-4)\displaystyle \div\frac{5^{2}+4\div 2}{8^{2}-9^{2}+8}$ $=12\displaystyle \div\frac{5^{2}+4\div 2}{8^{2}-9^{2}+8}=\qquad$... Exponents $=12\displaystyle \div\frac{25+4\div 2}{64-81+8}\qquad$...$\left\{\begin{array}{ll} numerator: & division\\ denominator: & left\ to\ right... subtract \end{array}\right.$ $=12\displaystyle \div\frac{25+2}{-17+8}\qquad$...$\left\{\begin{array}{ll} numerator: & add\\ denominator: & add \end{array}\right.$ $=12\displaystyle \div\frac{27}{-9}\qquad$... reduce the fraction by 9 $=12\div(-3)\qquad$... an odd number of minus signs... =$-4$
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