Answer
$\frac{3[4-3(-2)^2]}{2^2-2^4} = 2$
Work Step by Step
$\frac{3[4-3(-2)^2]}{2^2-2^4}$
$3[4-3(-2)^2]$ = $3[4-3(4)]$
$=3[4-12]$
$=3[-8]$
$=-24$
$2^2-2^4 = -12$
Hence,
$\frac{-24}{-12} = 2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 1 - Mid-Chapter Check Point - Page 53: 14
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