Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Mid-Chapter Check Point - Page 53: 13

Answer

True for all $x$

Work Step by Step

$4x - 2(1 - x) = 3(2x + 1) - 5$ Expand $-2(1 - x)$ = $-2+2x$ Expand $3(2x + 1)$ = $6x+3$ Rewrite the equation: $4x-2+2x= 6x+3-5$ $6x-2 = 6x-2$ Add 2 to both sides: $6x-2+2 = 6x-2+2$ $6x = 6x$ Subtract 6x from both sides: $6x-6x = 6x-6x$ $0=0$ Since both sides are equal, then the equation is true for all x.
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