Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 671: 90



Work Step by Step

$\frac{7}{2+3i}$ =$\frac{7}{2+3i}\times\frac{2-3i}{2-3i}$ =$\frac{7(2-3i)}{(2+3i)(2-3i)}$ =$\frac{14-21i}{2^{2}-(3i)^{2}}$ =$\frac{14-21i}{4-9i^{2}}$ =$\frac{14-21i}{4-9(-1)}$ =$\frac{14-21i}{13}$ =$\frac{14}{13}-\frac{21i}{13}$
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