Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - Chapter Review Exercises - Page 671: 102

Answer

$0$; $-4- 7\ i$; $-4+ 7\ i$

Work Step by Step

Given \begin{equation} h^3+8 h^2+65 h=0. \end{equation} This equation can be best solved by using the quadratic formula after factoring out $h$: \begin{equation} \begin{aligned} h^3+8 h^2+65 h&=0\\ h\left(h^2+8 h+65\right)&=0\\ h& = 0\\ h^2+8 h+65&= 0\\ h&=\frac{-8 \pm \sqrt{8^2-4 \cdot 1 \cdot 65}}{2 \cdot 1}\\ b&=\frac{-8 \pm 14 i}{2 }\\ &=-4\pm 7\ i. \end{aligned} \end{equation} The solution is \begin{equation} h= 0\quad , h=-4\pm 7\ i. \end{equation}
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