Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises: 36

Answer

$(v^5-5)^2$

Work Step by Step

The first term is $v^5$ squared, the last term is $5$ squared, and the middle term is twice the negative product of these two terms. Now we can factor the trinomial into a binomial squared. $v^{10}-10v^5+25$ $=(v^5-5)(v^5-5)$ $=(v^5-5)^2$
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