Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises - Page 279: 16

Answer

$(p+2)(p^2-2p+4)$

Work Step by Step

Use the formula $a^3+b^3=(a+b)(a^2-ab+b^2)$ to factor. $p^3+8$ $=(p+2)(p^2-2p+4)$
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