## Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole

# Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises - Page 279: 35

#### Answer

$(g^4+3)^2$

#### Work Step by Step

The first term is $g^4$ squared, the last term is $3$ squared, and the middle term is twice the product of these two terms. Now we can factor the trinomial into a binomial squared. $g^8+6g^4+9$ $=(g^4+3)(g^4+3)$ $=(g^4+3)^2$

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