Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises: 24

Answer

$(2x-3)(4x^2+6x+9)$; formula applied incorrectly.

Work Step by Step

Use the formula $a^3-b^3=(a-b)(a^2+ab+b^2)$ to factor. Paul did not apply the formula correctly in his work. $8x^3-27$ =$(2x-3)(4x^2+6x+9)$
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