Intermediate Algebra: Connecting Concepts through Application

$(2x-3)(4x^2+6x+9)$; formula applied incorrectly.
Use the formula $a^3-b^3=(a-b)(a^2+ab+b^2)$ to factor. Paul did not apply the formula correctly in his work. $8x^3-27$ =$(2x-3)(4x^2+6x+9)$