Answer
$(2x-3)(4x^2+6x+9)$; formula applied incorrectly.
Work Step by Step
Use the formula $a^3-b^3=(a-b)(a^2+ab+b^2)$ to factor. Paul did not apply the formula correctly in his work.
$8x^3-27$
=$(2x-3)(4x^2+6x+9)$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 3 - Exponents, Polynomials and Functions - 3.5 Special Factoring Techniques - 3.5 Exercises - Page 279: 24
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