Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - 3.2 Combining Functions - 3.2 Exercises - Page 250: 99

Answer

(a) $g(x)-f(x)=4x^2-1$ (b) $g(2)-f(2)=15$ (c) $f(x)g(x)= 4x^3+9x^2+3x+2$ (d) $f(2)g(2) = 76$

Work Step by Step

$f(x)=x+2$ $g(x)=4x^2+x+1$ (a) $g(x)-f(x)=4x^2+x+1 -(x+2)$ $g(x)-f(x)=4x^2+x+1 -x-2$ $g(x)-f(x)=4x^2-1$ .................. eq (1) (b) Putting $x=2$ in equation (1) $g(2)-f(2)=4(2)^2-1=16-1=15$ (c) $f(x)g(x)= (x+2)(4x^2+x+1)$ $f(x)g(x)= x(4x^2+x+1)+2(4x^2+x+1) $ $f(x)g(x)= 4x^3+x^2+x+8x^2+2x+2 $ $f(x)g(x)= 4x^3+x^2+8x^2+x+2x+2$ $f(x)g(x)= 4x^3+9x^2+3x+2$ ................... eq (2) (d) Putting $x=2$ in equation 2 $f(2)g(2) = 4(2^3)+9(2^2)+3(2)+2$ $f(2)g(2) = 4(8)+9(4)+3(2)+2=76$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.