Answer
$(a)f(4)+g(4)=18$
$(b)f(x)+g(x)=2x^2-2x+4$
$(c)f(4)g(4)= 0$
$(d)f(x)g(x)=10x^3-39x^2+44x-12 $
Work Step by Step
$f(x)=5x-2$
$g(x)=2x^2-7x+6$
(a)
$f(4)=5(4)-2=18$
$g(4)=2(2^2)-7(2)+6=0$
$f(4)+g(4)=18+0=18$
(b)
$f(x)+g(x)=5x-2+2x^2-7x+6$
$f(x)+g(x)=2x^2+5x-7x-2+6$
$f(x)+g(x)=2x^2-2x+4$
(c)
$f(4)g(4)=18\cdot 0=0$
(d)
$f(x)g(x)=(5x-2)(2x^2-7x+6)$
$f(x)g(x)=5x(2x^2-7x+6)-2(2x^2-7x+6) $
$f(x)g(x)=10x^3-35x^2+30x-4x^2+14x-12 $
$f(x)g(x)=10x^3-35x^2-4x^2+30x+14x-12 $
$f(x)g(x)=10x^3-39x^2+44x-12 $
