Answer
A) $7x^2y$.
B) $7x^2y$.
C) Yes.
D) $49x^4y^2$
Work Step by Step
Given $$\begin{aligned}
\frac{(7x^2y)^{10}}{(7x^2y)^{8}}.
\end{aligned}$$ Part A
The base of the exponent $10$ is $7x^2y$.
Part B
The base of the exponent $8$ is $7x^2y$.
Part C
Yes. The bases are the same and so, you can subtract the exponents.
Part D We have: $$\begin{aligned}
\frac{(7x^2y)^{10}}{(7x^2y)^{8}}&= (7x^2y)^{10-8}\\
&=(7x^2y)^{2} \\
&=49x^4y^2
\end{aligned}$$
