## Intermediate Algebra: Connecting Concepts through Application

$\frac{1}{125a^9b^3c^{21}}$
Use the outside exponent on each number within the parentheses. Remember to multiply the exponents of the bases by the outside exponent. In this case, we are multiplying $3$ by $-3$, $1$ by $-3,$ and $7$ by $-3$ for $a$, $b$, and $c$, respectively. Move any resulting negative exponents to the denominator in order to turn them positive, and leave any resulting numbers with positive exponents to the numerator (in this case, $1$). $(5a^3bc^7)^{-3}$ $5^{-3}a^{-9}b^{-3}c^{-21}$ $\frac{1}{125a^9b^3c^{21}}$