Intermediate Algebra: Connecting Concepts through Application

a. $C=5.29(x) + 400$ b. 929 dollars c. 160 proofs
a. $x=number of proofs$ $C=cost$ $C=5.29(x) + 400$ b. $C=5.29(100) +400$ $C=529+400$ $C=929$ c. $C=1250$ $1250=5.29(x)+400$ $1250-400=5.29(x)$ $850=5.29(x)$ $850\div5.29=x$ $x=160.68$ $x=160$