Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises - Page 12: 29


a. $C=125+100(d)$ b. $C=425$ c. 2 days

Work Step by Step

a. $C=cost$ $d=days$ $C=125+100(d)$ b. $d=3$ $C=125+100(3)$ $C=125+300$ $C=425$ c. $C=700\div2=350$ $350=125+100(d)$ $350-125=100(d)$ $225=100(d)$ $225\div100=d$ $d=2.25$ $d=2$
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