## Intermediate Algebra: Connecting Concepts through Application

a. $B=29.95+0.55(m)$ b. 71.20 dollars c. 127 miles
a. B=cost of renting a moving truck for one day, m=total miles driven. $B=29.95+0.55(m)$ b. m=75 $B=29.95+0.55(75)$ $B=29.95+41.25$ $B=71.20$ c. B=100 $100=29.95+0.55(m)$ $100-29.95=0.55(m)$ $70.05=0.55(m)$ $70.05\div0.55=m$ $m=127.36$ or 127 miles