Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises - Page 12: 33


a. $C=5500+1500+0.45(x)$ b. 8350 dollars c. 8000 snow cones

Work Step by Step

a. C=cost of selling snow cones, x=number of snow cones sold $C=5500+1500+0.45(x)$ b. x=3000 $C=7000+0.45(3000)$ $C=7000+1350$ $C=8350$ c. $C=10,600$ $10,600=7000+0.45(x)$ $10,600-7000=0.45(x)$ $3600=0.45(x)$ $3600\div0.45=x$ $x=8000$
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