Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review: 14

Answer

$t = 3, 9$

Work Step by Step

$|2t-12| = 6$ $2t-12 = 6$ $2t = 6 + 12$ $2t = 18$ $t = 9$ $-(2t-12) = 6$ $-2t + 12 = 6$ $-2t = 6 -12$ $-2t = -6$ $2t = 6$ $t = 3$ $t = 3, 9$ Check: When $t = 3$ $|2(3)-12| \overset{?}{=} 6$ $|6-12| \overset{?}{=} 6$ $|-6| \overset{?}{=} 6$ $6 = 6$ When $t = 9$ $|2(9)-12| \overset{?}{=} 6$ $|18-12| \overset{?}{=} 6$ $|6| \overset{?}{=} 6$ $6 = 6$
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