Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-6 - Cumulative Review - Page 547: 12

Answer

$x = \ln 89 - 5$

Work Step by Step

$e^{x+5} = 89$ $x + 5 = \ln 89$ $x = \ln 89 - 5$ Check: $e^{(\ln 89 - 5)+5} \overset{?}{=} 89$ $e^{\ln 89 - 5+5} \overset{?}{=} 89$ $e^{\ln 89} \overset{?}{=} 89$ $89 = 89$
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