Answer
$log_{\frac{1}{2}}5\approx-2.3219$
Work Step by Step
In order to evaluate the given logarithm, we can use the change of base formula.
$log_{b}a=\frac{log_{c}a}{log_{c}b}$ (where a, b, and c are positive real numbers and neither b nor c is 1)
For simplicity, we will use base 10, which is the base of the common logarithm.
Therefore, $log_{\frac{1}{2}}5=\frac{log_{10}5}{log_{10}\frac{1}{2}}=\frac{.6990}{-.3010}\approx-2.3219$.
