Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 585: 30

Answer

$\frac{1}{2}$

Work Step by Step

A common logarithm is a logarithm to base 10. As shown on page 580, when a common logarithm is written in the form $log (x)$, this is equivalent to the expression $log_{10}x$. Therefore, $log(\sqrt 10)=log_{10}\sqrt 10=\frac{1}{2}$. We know this, because $(10)^{\frac{1}{2}}=10^{\frac{1}{2}}=\sqrt 10$.
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