Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 585: 15

Answer

2

Work Step by Step

A common logarithm is a logarithm to base 10. As shown on page 580, when a common logarithm is written in the form $log(x)$, this is equivalent to the expression $log_{10}x$. Therefore, $log 100=log_{10}100=2$. We know this, because $10^{2}=100$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.