## Intermediate Algebra (6th Edition)

$x=\dfrac{5}{2}$
$\log_{5}x+\log_{5}10=2$ Combine the sum on the left side of the equation as the $\log$ of a product: $\log_{5}10x=2$ Rewrite in exponential form: $10x=5^{2}$ $10x=25$ Solve for $x$: $x=\dfrac{25}{10}=\dfrac{5}{2}$