Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 128



Work Step by Step

$\log_{5}x+\log_{5}10=2$ Combine the sum on the left side of the equation as the $\log$ of a product: $\log_{5}10x=2$ Rewrite in exponential form: $10x=5^{2}$ $10x=25$ Solve for $x$: $x=\dfrac{25}{10}=\dfrac{5}{2}$
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