Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 129



Work Step by Step

Using the properties of logarithms and since $\log_b x=y$ is equivalent to $b^y=x$, then, \begin{array}{l} \ln x-\ln 2=1\\\\ \ln \dfrac{x}{2}=1\\\\ \log_e \dfrac{x}{2}=1\\\\ \dfrac{x}{2}=e^1\\\\ x=2e .\end{array}
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