Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 598: 107



Work Step by Step

Using properties of logarithms, then, \begin{array}{l} \log(5x)-\log(x+1)=4\\\\ \log\left(\dfrac{5x}{x+1} \right)=4\\\\ \dfrac{5x}{x+1}=10^4\\\\ 5x=10,000(x+1)\\\\ 5x=10,000x+10,000\\\\ -9,995x=10,000\\\\ x=-\dfrac{10,000}{9,995} .\end{array}
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