# Chapter 9 - Review - Page 598: 127

$x=\dfrac{5}{2}$

#### Work Step by Step

Using the properties of logarithms and since $\log_b x=y$ is equivalent to $b^y=x$, then, \begin{array}{l} \log_5 x+\log_5 10=2\\\\ \log_5 x(10)=2\\\\ \log_5 10x=2\\\\ 10x=5^2\\\\ 10x=25\\\\ x=\dfrac{25}{10}\\\\ x=\dfrac{5}{2} .\end{array}

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