Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review: 92


$x\approx1.22$ mm

Work Step by Step

We are given that the formula $\ln(\frac{I}{I_{0}})=-kx$ can be used to solve radiation problems (where x is the depth in millimeters, I is the intensity of radiation, $I_{0}$ is the initial intensity, and k is a constant measure dependent on the material). In this case, we are given that $\frac{I}{I_{0}}=.02$ and $k=3.2$. $\ln(.02)=-3.2x$ Divide both sides by -3.2. $x=-\frac{\ln(.02)}{3.2}\approx1.22$ mm
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