Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review: 91


$x\approx1.67$ mm

Work Step by Step

We are given that the formula $\ln(\frac{I}{I_{0}})=-kx$ can be used to solve radiation problems (where x is the depth in millimeters, I is the intensity of radiation, $I_{0}$ is the initial intensity, and k is a constant measure dependent on the material). In this case, we are given that the intensity of the radiation passing through a lead shield is reduced to 3% of the original intensity (which means that $\frac{I}{I_{0}}=.03$) and $k=2.1$. $\ln(.03)=-2.1x$ Divide both sides by -2.1 $x=-\frac{\ln(.03)}{2.1}\approx1.67$ mm
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.