Answer
$log(.15)\approx-.8239$
Work Step by Step
To approximate $log(.15)$ on a calculator, we can press the following sequence of keys.
1. .15 then LOG
(OR)
2. LOG then .15 then ENTER
To four decimal places, $log(.15)\approx-.8239$.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Review - Page 597: 80
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