## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 9 - Review: 59

#### Answer

$x=\frac{17}{3}$

#### Work Step by Step

If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x\gt0$ and every real number $y$. Therefore, $log_{2}(3x-1)=4$ means $2^{4}=16=3x-1$. To solve for x, add 1 to both sides of the equation. $3x=17$ Divide both sides by 3. $x=\frac{17}{3}$

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