Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 503: 68

Answer

$2$

Work Step by Step

Let the whole number is $x$ A whole number increased by its square is two more than twice itself. $x+x^{2} = 2 + 2x$ $x+x^{2} - 2 - 2x = 0$ $x^{2} - x - 2 = 0$ By factoring, $(x-2)(x+1)=0$ $x=2$ or $x=-1$ The whole number should not be negative. Therefore the number is $2$
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