Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 503: 64

Answer

5.2 hours for large pipe, 7.2 hours for small pipe

Work Step by Step

large pipe and small pipe can fill in 3 hours large pipe can fill in $1/(x-2)$ hours, small pipe can fill in $1/x$ hours $1/(x-2) + 1/x = 1/3$ $3*x*(x-2)*(1/(x-2) + 1/x = 1/3)$ $3x + 3(x-2) = x(x-2)$ $3x +3x-6 = x^2-2x$ $6x-6=x^2-2x$ $6x-6-6x+6=x^2-2x-6x+6$ $0 = x^2-8x+6$ A graphing calculator showed $x=.838$ and $x=7.162$. However, $x\ne.838$ since the large pipe would have a negative time. $x=7.2$ hours $7.2-2=5.2$
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