Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 503: 67

Answer

$12$ or $-8$

Work Step by Step

Let the number be $x$ The product of the number and 4 less than the number is 96. $x(x-4)=96$ $x^{2}-4x=96$ $x^{2}-4x-96=0$ By factoring, $(x-12)(x+8)=0$ $x=12$ or $x=-8$ The number is $12$ or $-8$
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