Chapter 8 - Section 8.3 - Solving Equations by Using Quadratic Methods - Exercise Set - Page 503: 76

$z\lt5$

Multiplying both sides by the $LCD= 12 $ and using the properties of inequality, the solution to the given expression, $ \dfrac{z-2}{12}\lt\dfrac{1}{4} ,$ is \begin{array}{l}\require{cancel} 1(z-2)\lt3(1) \\\\ z-2\lt3 \\\\ z\lt3+2 \\\\ z\lt5 .\end{array}