Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 464: 116

Answer

$6-6i$

Work Step by Step

Using $i=\sqrt{-1}$ and the properties of radicals, the given expression, $ (8-\sqrt{-4})-(2+\sqrt{-16}) ,$ simplifies to \begin{array}{l}\require{cancel} 8-\sqrt{-4}-2-\sqrt{-16} \\\\= (8-2)+(-\sqrt{-4}-\sqrt{-16}) \\\\= (8-2)+(-\sqrt{-1}\cdot\sqrt{4}-\sqrt{-1}\cdot\sqrt{16}) \\\\= (8-2)+(-i\cdot\sqrt{(2)^2}-i\cdot\sqrt{(4)^2}) \\\\= (8-2)+(-i\cdot2-i\cdot4) \\\\= (8-2)+(-2i-4i) \\\\= 6-6i .\end{array}
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